Two point charge Q each are placed at a distance d apart. A third point charge q is placed at a distance x from mid-point on the perpendicular bisector. The value of x at which charge q will experience the maximum Coulomb's force is:

Option 1 - <p>&nbsp;x = d</p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>x</mi> <mo>=</mo> <mfrac> <mrow> <mi>d</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>x</mi> <mo>=</mo> <mfrac> <mrow> <mi>d</mi> </mrow> <mrow> <mroot> <mrow> <mn>2</mn> </mrow> <mrow></mrow> </mroot> </mrow> </mfrac> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>x</mi> <mo>=</mo> <mfrac> <mrow> <mi>d</mi> </mrow> <mrow> <mn>2</mn> <mroot> <mrow> <mn>2</mn> </mrow> <mrow></mrow> </mroot> </mrow> </mfrac> </mrow> </math> </span></p>
4 Views|Posted 6 months ago
Asked by Shiksha User
2 Answers
A
6 months ago
Correct Option - 4
Detailed Solution:

According to question, we can write

F C A = F C B = K q Q x 2 + ( d 2 ) 2 F = 2 F C A c o s θ = 2 K q Q x [ x 2 + ( d 2 ) 2 ] 3 2

For maxima of force

d F d x = 0 , s o

x = d 2 2

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A
6 months ago

According to question, we can write

F C A = F C B = K q Q x 2 + ( d 2 ) 2 ? F = 2 F C A c o s ? = 2 K q Q x [ x 2 + ( d 2 ) 2 ] 3 2

For maxima of force

d F d x = 0 , ? ? s o

x = d 2 2

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Physics Electrostatic Potential and Capacitance 2025

Physics Electrostatic Potential and Capacitance 2025

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