A uniform wire of resistance R is stretched uniformly to n times. It is then cut to form five wires of equal length. These wires are arranged as shown in figure. the effective resistance between A and C is

 

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <msup> <mrow> <mrow> <mi>n</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> <mi>R</mi> </mrow> </mrow> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> </mfrac> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <msup> <mrow> <mrow> <mi>n</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> <mi>R</mi> </mrow> </mrow> <mrow> <mrow> <mn>5</mn> </mrow> </mrow> </mfrac> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mi>n</mi> <mi>R</mi> </mrow> </mrow> <mrow> <mrow> <mn>5</mn> </mrow> </mrow> </mfrac> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mi>n</mi> <mi>R</mi> </mrow> </mrow> <mrow> <mrow> <mn>3</mn> </mrow> </mrow> </mfrac> </math> </span></p>
11 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
A
4 months ago
Correct Option - 2
Detailed Solution:

When wire is stretched uniformly

R R

R R ' = l n l 2 = 1 n 2  

R ' = n 2 R

When this elongated wire is cut into 5 parts, resistance of each part  

Effective resistance between A and C = n 2 R 5  

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Physics Current Electricity 2025

Physics Current Electricity 2025

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