A vehicle travels half the distance with speed  v and the remaining distance with speed 2 v . Its average speed is:

Option 1 -

3 v 4

Option 2 -

V 3

Option 3 -

2 v 3

Option 4 -

4 v 3

0 3 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:

    Average speed = 4 v 2 3 v

    = 4 v 3

    (d) Initial velocity  = - v j ˆ

    Final velocity = v i ˆ

    Change in velocity  = v i ˆ - ( - v j ˆ )

    = v ( i ˆ + j ˆ ) Momentum gain is along i ˆ + j ˆ

     Force experienced is along i ˆ + j ˆ

      Force experienced is in North-East direction.

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A
alok kumar singh

Kindly go through the solution '

 

A
alok kumar singh

Please find the solution below:

 

 

V
Vishal Baghel

[h] = ML2T-1

[E] = ML2T-2

[V] = ML2T-2C-1

[P] = MLT-1

 

A
alok kumar singh

According to question, we can write

 10 = 1 2 a t 2 . . . . . . . . . . . . . . . ( 1 ) a n d                        

1 0 + x = 1 2 a ( 2 t ) 2 . . . . . . . . . . . . . . . . ( 2 )  

X = 1 2 A [ ( 2 t ) 2 t 2 ] = 3 ( 1 2 a t 2 ) = 3 0 m  

 

V
Vishal Baghel

h = u²/2g, u = √2gh
Now, S = h/3
S = ut + ½at²
h/3 = √2ght - ½gt²
t² - 2√ (2h/g)t + 2h/3g = 0
Using quadratic formula for t:
t = ( 2√ (2h/g) ± √ (8h/g) - 4 (2h/3g) / 2
t = √ (2h/g) ± √ (2h/g - 2h/3g) = √ (2h/g) ± √ (4h/3g)
t? /t? = (√ (2h/g) - √ (4h/3g) / (√ (2h/g) + √ (4h/3g)
t? /t? = (√2 - √ (4/3) / (√2 + √ (4/3) = (√6 - 2)/ (√6 + 2)
(Note: There is a calculation error in the provided solution. Re-evaluating the physics.)
h/3 = (√2gh)t - ½gt²
(g/2)t² - (&

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