A vehicle travels half the distance with speed <math> <mi mathvariant="normal">v</mi> </math> and the remaining distance with speed <math> <mn>2</mn> <mi mathvariant="normal">v</mi> </math> . Its average speed is:

Average speed = 4 v 2 3 v = 4 v 3 (d) Initial velocity = - v j ˆ Final velocity = v i ˆ Change in velocity = v i ˆ - ( - v j ˆ ) = v ( i ˆ + j ˆ ) Momentum gain is along i ˆ + j ˆ ⇒ Force experienced is along i ˆ + j ˆ ⇒ Force experienced is in North-East direction.

A vehicle travels half the distance with speed&nbsp; <math> <mi mathvariant="normal">v</mi> </math> and the remaining distance with speed <math> <mn>2</mn> <mi mathvariant="normal">v</mi> </math> . Its average speed is: &lt;!-- [if !supportLineBreakNewLine]--&gt; &lt;!--[endif]--&gt;

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Motion in a Straight Line physics ncert solutions class 11th Physics Class 11th

A vehicle travels half the distance with speed $v$ and the remaining distance with speed $2 v$ . Its average speed is:

Option 1 -

$\frac{3 v}{4}$

Option 2 -

$\frac{V}{3}$

Option 3 -

$\frac{2 v}{3}$

Option 4 -

$\frac{4 v}{3}$

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Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a month ago

Correct Option - 4

Detailed Solution:

Average speed $= (\frac{4 v^{2}}{3 v})$ $(\frac{^{}}{})$

$= \frac{4 v}{3}$

(d) Initial velocity $= - v \hat{j}$

Final velocity $= v \hat{i}$

Change in velocity $= v \hat{i} - (- v \hat{j})$

$= v (\hat{i} + \hat{j})$ Momentum gain is along $\hat{i} + \hat{j}$

$\Rightarrow$ Force experienced is along $\hat{i} + \hat{j}$

$\Rightarrow$ Force experienced is in North-East direction.

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A vehicle travels half the distance with speed $v$ and the remaining distance with speed $2 v$ . Its average speed is:

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A vehicle travels half the distance with speed $v$ and the remaining distance with speed $2 v$ . Its average speed is: