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A wire of resistance R1 is drawn out so that its length is increased by twice of its original length. The ratio of new resistance to original resistance is:

Option 1 -

9 : 1

Option 2 -

1 : 9

Option 3 -

4 : 1

Option 4 -

3 : 1

0 3 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 1


    Detailed Solution:

    R 2 = ρ 2 l A / 2 = 4 ρ l A = 4 R 1
    R 2 R 1 = 4 1 → 4 : 1

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