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A zener diode having zener voltage 8V and power dissipation rating of 0.5W is connected across a potential divider arranged with maximum potential drop across zener diode is as shown in the diagram.

0 3 Views | Posted a month ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago

    P z = V z l z ⇒ 0 . 5 = 8 l z ⇒ l z = l P = 1 1 6 A m p

    When zener is connected across a potential divider arranged with maximum potential drop across zener diode, then

    V P = V − V z = 2 0 − 8 = 1 2  volt Potential difference across protective resistance RP

    R P = V P I P = 1 2 1 6 = 1 9 2     A m p .

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