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An electrical device draws 2KW power from AC mains (voltage 223V(rms)=) 50000 V . The current differs (lags) in phase by ∅ (tan ∅ = - 3 / 4 ) as compared to voltage . find

(a) R

(b) XL-XC  (c) Im. Another device has twice the values for R,XcandXL. how the answer affected?

0 3 Views | Posted 4 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    This is a long answer type question as classified in NCERT Exemplar

    Power drawn, p= 2KW= 2000W

    tan ∅ =-3/4

    P=V2/Z

    Z=V2/P= 223×2232×103 =25

    Z = R2+ (XL-XC)2

    25= R2+ (XL-XC)2

    625 = R2+ (XL-XC)2 ………… (1)

    tan ∅ = XL-XCR = ¾

    XL-XC= 3R/4

    Use this in eqn 1

    625= R2+ (3R/4)2 = R2+9R2/16

    625 = 25R2/16, R= 20ohm

    XL-XC=15ohm

    Im= 2 I= 2V/Z = 223×225 = 12.6A

    If R, XL and Xc are all doubled, tan ∅ does not change . Z is doubled, current is halved. So power is also halved.

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