An electron, a doubly ionized helium ion (He??) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelength λe, λHe?? and λp is:
An electron, a doubly ionized helium ion (He??) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelength λe, λHe?? and λp is:
Option 1 -
λe > λHe⁺⁺ > λp
Option 2 -
λe < He = p
Option 3 -
λe > λp > λHe⁺⁺
Option 4 -
λe < p < He
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:λ=h/p, p=√2mk. λ∝1/√m
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