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An electron (of mass m ) and a photon have the same energy E in the range of a few eV. The ratio of the de-Broglie wavelength associated with the electron and the wavelength of the photon is ( c =  speed of light in vacuum)

Option 1 -

c ( 2 m E ) 1 / 2

Option 2 -

1 c E 2 m 1 / 2

Option 3 -

1 c 2 E m 1 / 2

Option 4 -

E 2 m 1 / 2

0 3 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    3 months ago
    Correct Option - 3


    Detailed Solution:

    λ electron   = h 2 m E λ electron   λ photon   = 1 c E 2 m

    λ photon   = h c E

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