An engine is attached to a wagon through a shock absorber of length 1.5m. The system with a total mass of 40,000kg is moving with a speed of 75 kmh-1 when the brakes are applied to bring it to rest. In the process of the system being  brought to rest, the spring of the shock absorber gets compressed by 1.0m. If 90% of energy of the wagon is lost due to friction, the spring constant is________* 105 N/m.

4 Views|Posted 7 months ago
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7 months ago

By work energy theorem

Work done = change in K.E.

Work done by friction work done by spring

= 0 1 2 m V 2              

As 90% of K.E. is losed by friction so that

9 0 1 0 0 ( 1 2 m V 2 ) 1 2 K x 2 = 1 2 m V 2                

-K -> -16 * 105

K = 16 * 105

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Physics Work, Energy and Power 2021

Physics Work, Energy and Power 2021

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