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An inductor of reactance 1 ? and a resistor of 2 ? are connected in series to the terminals of a 6 V (rms) AC source. The power dissipated in the circuit is

(a) 8 W               

(b) 12 W

(c) 14.4 W         

(d) 18 W

0 2 Views | Posted 4 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    This is a multiple choice answer as classified in NCERT Exemplar

    Average power dissipated is ErmsIrmscos ∅

    Z= R2+XL2

    = 1+4 = 5

    Irms= 6/ 5 A

    cos ∅ =R/Z=2/ 5

    pav= 6 ×65×25 = 14.4W

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