An insect is at the bottom of a hemispherical ditch of radius 1 m. It crawls up the ditch but starts slipping after it is at height h from the bottom. If the coefficient of friction between the ground and the insect is 0.75, then h is: (g = 10 ms?²)
An insect is at the bottom of a hemispherical ditch of radius 1 m. It crawls up the ditch but starts slipping after it is at height h from the bottom. If the coefficient of friction between the ground and the insect is 0.75, then h is: (g = 10 ms?²)
Option 1 - <p>0.20 m<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>0.45 m</p>
Option 3 - <p>0.60 m<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>0.80 m</p>
7 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
V
Answered by
7 months ago
Correct Option - 1
Detailed Solution:
µ=tanθ ⇒ 3/4=tanθ ⇒ θ=37°
h = R-Rcosθ = 1-1 (4/5)=0.2m
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