As shown in the figure, a potentiometer wire of resistance 2 0 Ω  and length 300cm is connected with resistance box (R.B) and a standard cell of emf 4 V. For a resistance 'R' of resistance box introduced into the circuit, the null point for a cell of 20 mV is found to be 60 cm. The value of 'R' is __________ Ω .

6 Views|Posted 6 months ago
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1 Answer
V
6 months ago

R A B = 2 0 Ω

L = 300 cm

Null point is at 60 cm from A, so

2 0 m V = 4 R + 2 0 * 2 0 * ( 6 0 3 0 0 ) * 1 0 3

2 0 = 1 6 R + 2 0 * 1 0 3

R = 1 5 6 0 0 2 0 = 7 8 0 Ω

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Physics Current Electricity 2025

Physics Current Electricity 2025

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