Assuming the nitrogen molecule is moving with r.m.s. velocity at 400 K, the de-Broglie wavelength of nitrogen molecule is close to:
(Given: nitrogen molecule weight: 4.64 × 10⁻²⁶ kg, Boltzman constant: 1.38 × 10⁻²³ J/K, Planck constant: 6.63 × 10⁻³⁴Js)
Assuming the nitrogen molecule is moving with r.m.s. velocity at 400 K, the de-Broglie wavelength of nitrogen molecule is close to:
(Given: nitrogen molecule weight: 4.64 × 10⁻²⁶ kg, Boltzman constant: 1.38 × 10⁻²³ J/K, Planck constant: 6.63 × 10⁻³⁴Js)
Option 1 -
0.24 Å
Option 2 -
0.20 Å
Option 3 -
0.34 Å
Option 4 -
0.44 Å
Asked by Shiksha User
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1 Answer
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Correct Option - 1
Detailed Solution:de-Broglie wavelength
λ = h/mv = h / √ (3kT/m * m) = h / √ (3mkT)
λ = (6.63 × 10? ³? ) / √ (3 × 4.64 × 10? ²? × 1.38 × 10? ²³ × 400)
λ = (6.63 / 2.77) × 10? ¹¹ = 2.39 × 10? ¹¹ m ≈ 0.24Å
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