Physics Semiconductor Devices Semiconductor Devices Overview Class 12th Physics

Boolean relation at the output state-Y for the following circuits is:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mover accent="true"> <mrow> <mrow> <mi>A</mi> </mrow> </mrow> <mi>‾</mi> </mover> <mo>⋅</mo> <mover accent="true"> <mrow> <mrow> <mi>B</mi> </mrow> </mrow> <mi>‾</mi> </mover> </math> </span><br></p>

Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mi>A</mi> <mo>+</mo> <mi>B</mi> </math> </span></p>

Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mover accent="true"> <mrow> <mrow> <mi>A</mi> </mrow> </mrow> <mi>‾</mi> </mover> <mo>+</mo> <mover accent="true"> <mrow> <mrow> <mi>B</mi> </mrow> </mrow> <mi>‾</mi> </mover> </math> </span></p>

Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mi>A</mi> <mo>⋅</mo> <mi>B</mi> </math> </span></p>

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Answered by

Raj Pandey | Contributor-Level 9

5 months ago

Correct Option - 1

Detailed Solution:

First part of figure shown is or GATE and Second part of figure shown is NOT GATE So, $Y_{P} = O R + N O T =$ NOR GATE $Y = \overset{?}{A + B} = \overline{A} \cdot \overline{B}$

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