Calculate the ratio of the mean free paths of the molecules of two gases having molecular diameters 1Å and 2 Å . The gases may be considered under identical conditions of temperature, pressure and volume.

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Payal Gupta | Contributor-Level 10

8 months ago

This is a short answer type question as classified in NCERT Exemplar

Mean free path l=1/ $\sqrt[]{2} d^{2} n$

So n= number of molecules /volume

d = diameter of the molecule

l $\propto \frac{1}{d^{2}}$

d₁=1A^o, d₂=2A^o

l $\propto \frac{1}{d^{2}}$

$\frac{l_{1}}{l_{2}} = {(\frac{d_{2}}{d_{1}})}^{2} = {(\frac{2}{1})}^{2} = \frac{4}{1}$

l₁:l₂=4:1

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physics ncert solutions class 11th 2023

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