This is a short answer type question as classified in NCERT Exemplar
E=E0sinwt
And current I=I0sin (wt )
Power, P= EI = E0sinwt = E0I0sinwtsin (wt+ )
= [cos ]………… (1)
Pav= cos =VrmsIrmscos ………. (2)
From eqn 1 ……But when cos
< cos (2wt+
P<0 power can be nagative of an AC source
From eqn 2……… Pav>0
cos =R/Z>0 average power can not be negative
<p><span data-teams="true">This is a short answer type question as classified in NCERT Exemplar</span></p><p>E=E<sub>0</sub>sinwt</p><p>And current I=I<sub>0</sub>sin (wt <math><mfrac><mrow><mrow><mo>+</mo></mrow></mrow><mrow><mrow><mo>-</mo></mrow></mrow></mfrac><mi>∅</mi></math> )</p><p>Power, P= EI = E<sub>0</sub>sinwt = E<sub>0</sub>I<sub>0</sub>sinwtsin (wt+ <math><mi>∅</mi></math> )</p><p>= <math><mfrac><mrow><mrow><msub><mrow><mrow><mi>E</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub><msub><mrow><mrow><mi>I</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub></mrow></mrow><mrow><mrow><mn>2</mn></mrow></mrow></mfrac></math> [cos <math><mi>∅</mi><mo>-</mo><mi>c</mi><mi>o</mi><mi>s</mi><mo> (</mo><mn>2</mn><mi>w</mi><mi>t</mi><mo>+</mo><mi>∅</mi><mo>)</mo></math> ]………… (1)</p><p>Pav= <math><mfrac><mrow><mrow><msub><mrow><mrow><mi>V</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub></mrow></mrow><mrow><mrow><mroot><mrow><mrow><mn>2</mn></mrow></mrow><mrow></mrow></mroot></mrow></mrow></mfrac><mfrac><mrow><mrow><msub><mrow><mrow><mi mathvariant="normal">I</mi></mrow></mrow><mrow><mrow><mn>0</mn></mrow></mrow></msub></mrow></mrow><mrow><mrow><mroot><mrow><mrow><mn>2</mn></mrow></mrow><mrow></mrow></mroot></mrow></mrow></mfrac></math> cos <math><mi>∅</mi></math> =V<sub>rms</sub>I<sub>rms</sub>cos <math><mi>∅</mi></math> ………. (2)</p><p>From eqn 1 ……But when cos <math><mi>∅</mi></math> < cos (2wt+<math><mi>∅)</mi></math></p><p>P<0 power can be nagative of an AC source</p><p>From eqn 2……… P<sub>av</sub>>0</p><p>cos <math><mi>∅</mi></math> =R/Z>0 average power can not be negative</p>
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