Consider two uniform discs of the same thickness and different radii
and
made of the same material. If the ratio of their moments of inertia
and
, respectively, about their axes is
then the value of
is:
Consider two uniform discs of the same thickness and different radii and made of the same material. If the ratio of their moments of inertia and , respectively, about their axes is then the value of is:
Option 1 -
4
Option 2 -
Option 3 -
2
Option 4 -
(Rotational Mechanics)
-
1 Answer
-
Correct Option - 3
Detailed Solution:
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mg = 10 × 10
= 100 of
NA = reaction force offered by the wall
reaction force offered by the floor.
By NLM 1
Translational fB = NA
NB = mg = 100N
Ac2 + Bc2 = AB2
Ac2 = 34 – 9
Ac = 5m
Rotational equilibrium
mg
NA = 50 cot
Now cot =
NA =
Therefore, NA = - (i)
- (2)
a = 6t2 – 2t, of t 20, w = 10 rad/sec
, q = 4 rad
=
A/c to question
f + 76 = 2f
f = 76
last frequency
= f + 76 = 2 × 76
= 152 H2
K.ER (Rotational) = - (1)
- (2)
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So, momentum = mv = m × 0 = 0
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