Deutrium was discovered in 1931by Harold Urey by measuring the small change in wavelength for a particular transition in 1H and 2 This is because, the wavelength of transition depends to a certain extent on the nuclear mass. If nuclear motion is taken into account, then the electrons and nucleus revolve around their common centre of mass. Such a system is equivalent to a single particle with a reduced mass μ , revolving around the nucleus at a distance equal to the electron-nucleus separation. Here μ = meM / ( me + M ) where M is the nuclear mass and me is the electronic mass. Estimate the percentage difference in wavelength for the 1st line of the Lyman series in . 1H and 2H . (Mass of 1H nucleus is 1.6725 × 10-27kg , mass of 1H nucleus is 3.3374 × 10-27kg 3.3374 × 10-27
?g , Mass of electron = 9.109 × 10-31 kg ).
Deutrium was discovered in 1931by Harold Urey by measuring the small change in wavelength for a particular transition in 1H and 2 This is because, the wavelength of transition depends to a certain extent on the nuclear mass. If nuclear motion is taken into account, then the electrons and nucleus revolve around their common centre of mass. Such a system is equivalent to a single particle with a reduced mass μ , revolving around the nucleus at a distance equal to the electron-nucleus separation. Here μ = meM / ( me + M ) where M is the nuclear mass and me is the electronic mass. Estimate the percentage difference in wavelength for the 1st line of the Lyman series in . 1H and 2H . (Mass of 1H nucleus is 1.6725 × 10-27kg , mass of 1H nucleus is 3.3374 × 10-27kg 3.3374 × 10-27 ?g , Mass of electron = 9.109 × 10-31 kg ).
-
1 Answer
-
This is a Long Answer Type Questions as classified in NCERT Exemplar
Explanation- total energy of electron
E=
The frequency hv=
=
= =
=
When me<
after solving we get 2.714
Similar Questions for you
Kindly go through the solution
Change in surface energy = work done
|DE0| = –10.2
]
= 3 m/s
n = 4
Number of transitions =
Kinetic energy: Potential energy = 1 : –2
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 686k Reviews
- 1800k Answers