Draw a graph to show the variation of P.E., K.E. and total energy of a simple harmonic oscillator with displacement.

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Payal Gupta | Contributor-Level 10

7 months ago

This is a multiple choice answer as classified in NCERT Exemplar

Potential energy of a simple harmonic oscillator is = ½ kx²=1/2mw²x²

K=mw²

When x=0 PE=0

When x= $? A$ , PE=maximum

=1/2 mw²A²

KE of a simple harmonic oscillator =1/2 mv²

= 1/2 m [w $\sqrt[]{A^{2} - x^{2}}$ ] ²

= ½ mw² (A²-x²)

This is also parabola if plot KE against dis

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Physics NCERT Exemplar Solutions Class 11th Chapter Fourteen 2025

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