Nuclei Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen Binding Energy Class 12th Physics

Find the binding energy per neucleon for $_{50}^{120} S n$ . Mass of proton $m_{p} = (A) 1.00783 U$ , mass of neutron $m_{n} = (A) 1.00867 U$ and mass of tin nucleus $m_{S n} = 119.902199 U$ . (take $1 U = 931 M e V$ )

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mn>8.5</mn> <mi mathvariant="normal">M</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">V</mi> </math> </span></p>

Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mn>9.0</mn> <mi mathvariant="normal">M</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">V</mi> </math> </span></p>

Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mn>7.5</mn> <mi mathvariant="normal">M</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">V</mi> </math> </span></p>

Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mn>8.0</mn> <mi mathvariant="normal">M</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">V</mi> </math> </span> (Atoms and Nuclei)</p>

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Alok Kumar Singh | Contributor-Level 10

7 months ago

Correct Option - 4

Detailed Solution:

Sol. $\Rightarrow {\overset{?}{V}}_{1} = 2 \overset{?}{U_{c m}} - \overset{?}{U_{1}} \Rightarrow 2 [\frac{m / 2 V_{o}}{\frac{m}{2} + \frac{m}{3}}] - V_{o}$

$\Rightarrow \frac{6}{5} V_{o} - V_{o} \Rightarrow \frac{V_{0}}{5}$

$\Rightarrow λ_{o} = \frac{h c}{(\frac{m}{2} V_{o})} λ_{f} = \frac{h c}{(\frac{M}{2} \frac{V_{o}}{5})}$

$\Rightarrow Δ λ = \frac{8 h c}{{m V}_{o}}$

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Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen 2025

Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen 2025

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