First, a set of n equal resistors of 10 Ω  each are connected in series to a battery of emf 20V and internal resistance 10 Ω . A current I is observed to flow. Then, the n resistors are connected in parallel to the same battery. It is observed that the current is increases 20 times, then the value of n is………

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6 months ago

In series Req = nR = 10n

l s = 2 0 1 0 + 1 0 n = 2 1 + n

In parallel R e q = 1 0 n

l ρ l s = 2 0 = 2 n / 1 + n 2 / 1 + n

n = 20

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Physics Current Electricity 2025

Physics Current Electricity 2025

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