Five equal resistances are connected in a network as shown in figure. The net resistance between  the points A and B is

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>3</mn> <mi>R</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span></p>
Option 2 - <p>R</p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mi>R</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span></p>
Option 4 - <p>2R</p>
14 Views|Posted 6 months ago
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1 Answer
P
6 months ago
Correct Option - 2
Detailed Solution:

Given circuit can be re-drawn and it becomes case of balanced Wheatstone bride

R A B = ( 2 R ) ( 2 R ) 2 R + 2 R = R

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Physics Current Electricity 2025

Physics Current Electricity 2025

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