For a free body diagram shown in the figure, the four forces are applied in the 'x' and 'y' directions. What additional forces must be applied and at what angle with positive x-axis so that the net acceleration of body is zero?

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mroot> <mrow> <mn>2</mn> </mrow> <mrow></mrow> </mroot> <mi>N</mi> <mo>,</mo> <mn>4</mn> <mn>5</mn> <mo>°</mo> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mroot> <mrow> <mn>2</mn> </mrow> <mrow></mrow> </mroot> <mi>N</mi> <mo>,</mo> <mn>1</mn> <mn>3</mn> <mn>5</mn> <mo>°</mo> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>2</mn> </mrow> <mrow> <mroot> <mrow> <mn>3</mn> </mrow> <mrow></mrow> </mroot> </mrow> </mfrac> <mi>N</mi> <mo>,</mo> <mn>3</mn> <mn>0</mn> <mo>°</mo> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>2</mn> <mi>N</mi> <mo>,</mo> <mn>4</mn> <mn>5</mn> <mo>°</mo> </mrow> </math> </span></p>
3 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
P
8 months ago
Correct Option - 1
Detailed Solution:

Let additional force is F , so

F+5 (+i^)+6 (i^)+7 (+j^)+8 (j^)=0

F (i^+j^)=0F=i^+j^F=2N, 45°

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