For a gas C? - C? = R in a state P and C? - C? = 1.10 R in a state Q, T? and T? are the temperatures in two different states P and Q respectively. Then
For a gas C? - C? = R in a state P and C? - C? = 1.10 R in a state Q, T? and T? are the temperatures in two different states P and Q respectively. Then
Option 1 -
Tₚ < T
Option 2 -
Tₚ = 0.9 Tᵩ
Option 3 -
Tₚ > Tᵩ
Option 4 -
Tₚ = Tᵩ
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:C? = dQ/ndT = (dU + pdV)/ndT
= C? + (pdV/ndT)
C? - C? = pdV/ndT = R - For ideal Gas [Box: PV = nRT, pdV = nRdT]
C? - C? = 1.1R - For Non – Idea gas (for Real gas)
And Real gas behaves as ideal gas at high temperature & low pressure.
∴ T_B > T_A
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