For a gas C? - C? = R in a state P and C? - C? = 1.10 R in a state Q, T? and T? are the temperatures in two different states P and Q respectively. Then

Option 1 - <p>Tₚ &lt; Tᵩ</p>
Option 2 - <p>Tₚ = 0.9 Tᵩ<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 3 - <p>Tₚ &gt; Tᵩ<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>Tₚ = Tᵩ</p>
4 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
R
6 months ago
Correct Option - 3
Detailed Solution:

C? = dQ/ndT = (dU + pdV)/ndT
= C? + (pdV/ndT)
C? - C? = pdV/ndT = R - For ideal Gas [Box: PV = nRT, pdV = nRdT]
C? - C? = 1.1R - For Non – Idea gas (for Real gas)
And Real gas behaves as ideal gas at high temperature & low pressure.
∴ T_B > T_A

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Physics Thermodynamics 2025

Physics Thermodynamics 2025

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