Physics Ncert Solutions Class 12th Semiconductor Electronics: Materials, Devices and Class 12th Physics

For a transistor a and b are given as $α = \frac{I_{C}}{I_{E}} a n d β = \frac{I_{C}}{I_{B}} .$ Then the correct relation between a and b will be:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>β</mi> <mo>=</mo> <mfrac> <mrow> <mi>α</mi> </mrow> <mrow> <mn>1</mn> <mo>−</mo> <mi>α</mi> </mrow> </mfrac> </mrow> </math> </span></p>

Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>α</mi> <mi>β</mi> <mo>=</mo> <mn>1</mn> </mrow> </math> </span></p>

Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>α</mi> <mo>=</mo> <mfrac> <mrow> <mi>β</mi> </mrow> <mrow> <mn>1</mn> <mo>−</mo> <mi>β</mi> </mrow> </mfrac> </mrow> </math> </span></p>

Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>α</mi> <mo>=</mo> <mfrac> <mrow> <mn>1</mn> <mo>−</mo> <mi>β</mi> </mrow> <mrow> <mi>β</mi> </mrow> </mfrac> </mrow> </math> </span></p>

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Alok Kumar Singh | Contributor-Level 10

6 months ago

Correct Option - 1

Detailed Solution:

β $= \frac{I_{C}}{I_{E}} = \frac{I_{C}}{I_{E} - I_{C}} = \frac{I_{C} / I_{E}}{1 - l_{C} / I_{E}} = \frac{α}{1 - α}$

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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