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For the given circuit, the power across zener diode is________mW.

 

0 3 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago

    Current through zener diode,

    l z = 2 4 − 1 0 1 − 1 0 5 m A = 1 2 m A              

    Power across zener diode,

    P z = V z . l z = 1 0 × 1 2 = 1 2 0 m W          

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ibattery= 1 0 ? 3 1 0 0 0  = 7mA

i2kW = 3 2 0 0 0  =1.5 mA

iz = (7 – 1.5) mA

= 5.5mA

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