Given below are two statements:

Statement I : In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit (E1) to higher energy orbit (E2), is given as hf = E1 = E2

Statement II : The jumping of electron from higher energy orbit (E2) to lower energy orbit (E1) is associated with frequency of radiation given as f = (E2 – E1) / h

This condition is Bohr’s frequency condition.

In the light of the above statements, choose the correct answer from the options given below:

Option 1 -

Both statement I and statement II are true.                       

Option 2 -

Both statement I and statement II are false

Option 3 -

Statement I is correct but statement II is false

Option 4 -

Statement I is incorrect but statement II is true.

0 3 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    2 months ago
    Correct Option - 4


    Detailed Solution:

    E 2 > E 1

    For statement 1

                  hf = E1  - E2

    Since, E2 > E1

    So, it should be

    hf = E2 – E1

    Therefore statement 1 is wrong

    For statement 2

    For the jumping of electron from higher energy orbit

    (E2) to lower energy orbit (E1)

    hf = E2 – E1

      f = E 2 E 1 h              

    Statement (2) is correct

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Kindly go through the solution

 

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