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Mechanical Properties of Solids physics ncert solutions class 11th Physics Class 11th Physics NCERT Exemplar Solutions Class 11th Chapter Nine

Identical springs of steel and copper are equally stretched. On which, more work will have to be done?

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Payal Gupta | Contributor-Level 10

4 months ago

This is a short answer type question as classified in NCERT Exemplar

Work done =1/2F $\times ?$ l

As spring of both are equally compressed

So Young’s modulus Y= $\frac{F}{A} \times \frac{l}{? l}$ as $? l$ is inversely proportional to young’s modulus

And also we know W is inversely proportional to young’s modulus

So $\frac{W_{s t e e l}}{W_{c o p p e r}} = \frac{Y_{c o p p e r}}{Y_{s t e e l}} 1$

W_steelcopper

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