In a transistor if I C E E = α and I C I B = β . If α varies between 20 21 and 100 101 , then the value of β lies between

The relation between α and β is given as β = α 1 - α β 1 = 20 21 1 - 20 21 = 20 β 2 = 100 101 1 - 100 101 = 100

In a transistor if $\frac{I_{C}}{E_{E}} = α$ and $\frac{I_{C}}{I_{B}} = β$ . If $α$ varies between $\frac{20}{21}$ and $\frac{100}{101}$ , then the value of $β$ lies between

Option 1 - <math> <mn>1</mn> <mo>-</mo> <mn>10</mn> </math>

Option 2 - <math> <mn>0.95</mn> <mo>-</mo> <mn>0.99</mn> </math>

Option 3 - <math> <mn>200</mn> <mo>-</mo> <mn>300</mn> </math>

Option 4 - <math> <mn>20</mn> <mo>-</mo> <mn>100</mn> </math>

2 Views|Posted 4 months ago

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Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 4

Detailed Solution:

The relation between $α$ and $β$ is given as

$β = \frac{α}{1 - α}$

$β_{1} = \frac{\frac{20}{21}}{1 - \frac{20}{21}} = 20$

$β_{2} = \frac{\frac{100}{101}}{1 - \frac{100}{101}} = 100$

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Physics Ncert Solutions Class 12th 2023

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