In a Vernier Calipers, 10 divisions of Vernier scale is equal to the 9 divisions of main scale. Then both jaws of Vernier calipers touch each other, the zero of the Vernier scale is shifted to the left of zero of the main scale and 4th Vernier scale division exactly coincides with the main scale reading. One main scale division is equal to 1mm. While measuring diameter of a spherical body, the body is held between two jaws. It is now observed that zero of the Vernier scale lies between 30 and 31 divisions of main scale reading and 6th Vernier scale division exactly coincides with the main scale reading. The diameter of the spherical body will be:
In a Vernier Calipers, 10 divisions of Vernier scale is equal to the 9 divisions of main scale. Then both jaws of Vernier calipers touch each other, the zero of the Vernier scale is shifted to the left of zero of the main scale and 4th Vernier scale division exactly coincides with the main scale reading. One main scale division is equal to 1mm. While measuring diameter of a spherical body, the body is held between two jaws. It is now observed that zero of the Vernier scale lies between 30 and 31 divisions of main scale reading and 6th Vernier scale division exactly coincides with the main scale reading. The diameter of the spherical body will be:
Option 1 -
3.02 cm
Option 2 -
3.06 cm
Option 3 -
3.10 cm
Option 4 -
3.20 cm
-
1 Answer
-
Correct Option - 3
Detailed Solution:1 MSD = 1mm
9 MSD = 10 VSD
1VSD = 0.9 MSD = 0.9 mm
Least count = 1 MSD – 1 VSD
= 0.1 mm = 0.01 cm
Zero Error = (10 – 4) × 0.1 = 0.6 mm
Reading = MSR + VSR – Zero error
= 3 cm + 6 × 0.01 – (0.06)
= 3.12 cm 3.10 cm
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers