In connection with the circuit drawn below, the value of current flowing through 2 k Ω  resistor is________ × 10-4A.

 

0 3 Views | Posted 4 weeks ago
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    Answered by

    alok kumar singh | Contributor-Level 10

    4 weeks ago

    Potential difference across 2k Ω  is 5V, thus current through it,

    i = 5 2 × 1 0 3 = 2 5 × 1 0 4 A .           

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Let us assume the potential at A = V_A = 0.
Now at junction C, according to KCL
i? + i? = i?
1 A + i? = 2 A


i? = 2 A
Now analyse potential along ACDB
V_A + 1 + i? (2) - 2 = V_B
0 + 1 + 2 (1) - 2 = V_B
V_B = 3 - 2
V_B = 1amp.

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