In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point B with respect to the point A is:

Option 1 - +1 V

Option 2 - -1 V

Option 3 - +2V

Option 4 - -2V

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Answered by

Vishal Baghel | Contributor-Level 10

5 months ago

Correct Option - 1

Detailed Solution:

Let us assume the potential at A = V_A = 0.
Now at junction C, according to KCL
i? + i? = i?
1 A + i? = 2 A

i? = 2 A
Now analyse potential along ACDB
V_A + 1 + i? (2) - 2 = V_B
0 + 1 + 2 (1) - 2 = V_B
V_B = 3 - 2
V_B = 1amp.

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