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In the Auger process, an atom maizes a transition to a lower state without emitting a photon. The excess energy is transferred to an outer electron which may be ejected by the atom (This is called an Auger electron). Assuming the nucleus to be massive, calculate the kinetic energy of an n = 4 Auger electron emitted by Chromium by absorbing the energy from a n – 2 to n = 1 transition.

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    Answered by

    Vishal Baghel | Contributor-Level 10

    3 months ago

    This is a Long Answer Type Questions as classified in NCERT Exemplar

    Explanation- the energy of nth state En=-Z2R 1 n 2  where R is constant and Z=24

    The energy release ina transition from 2 to 1 ? E = Z 2 R 1 - 1 4 = 3 4 Z 2 R

    The energy required to eject a n=4 electron is E4= Z2R1/16

    So kinetic energy of auger electron is, KE= Z2R (3/4-1/16)=1/16Z2R

    = 11 16 × 24 × 24 × 13.6 e V = 5385.6 e V

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