In the circuit, the logical value of A = 1 or B = 1 when potential at A or B is 5 V and the logical value of A = 0 or B = 0 when potential at A or B is 0 V. The truth table of the given circuit will be:

 

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mtable> <mtr columnalign="center"> <mtd columnalign="center"> <mi>A</mi> </mtd> <mtd columnalign="center"> <mi>B</mi> </mtd> <mtd columnalign="center"> <mi>Y</mi> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> </mtr> <mtr columnalign="center"> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> </mtr> <mtr columnalign="center"> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> </mtr> </mtable> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mtable> <mtr columnalign="center"> <mtd columnalign="center"> <mi>A</mi> </mtd> <mtd columnalign="center"> <mi>B</mi> </mtd> <mtd columnalign="center"> <mi>Y</mi> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> </mtr> <mtr columnalign="center"> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> </mtr> <mtr columnalign="center"> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> </mtr> </mtable> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mtable> <mtr columnalign="center"> <mtd columnalign="center"> <mi>A</mi> </mtd> <mtd columnalign="center"> <mi>B</mi> </mtd> <mtd columnalign="center"> <mi>Y</mi> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> </mtr> <mtr columnalign="center"> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> </mtr> <mtr columnalign="center"> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> </mtr> </mtable> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mtable> <mtr columnalign="center"> <mtd columnalign="center"> <mi>A</mi> </mtd> <mtd columnalign="center"> <mi>B</mi> </mtd> <mtd columnalign="center"> <mi>C</mi> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> </mtr> <mtr columnalign="center"> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> </mtr> <mtr columnalign="center"> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>1</mn> </mtd> <mtd columnalign="center"> <mn>0</mn> </mtd> </mtr> </mtable> </mrow> </math> </span></p>
47 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
V
6 months ago
Correct Option - 1
Detailed Solution:

When both A and B have logical value 'l' both diode are reverse bias and current will flow in resistor hence output will be 5 volt i.e. logical value '1'.

In all other case conduction will take place hence output will be zero value i.e. logical value 'o'.

So truth table is

A            B            Y

...Read more

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Similar Questions for you

Here  Δ V c = 0 . 5 V , Δ i c = 0 . 0 5 m A = 0 . 0 5 × 1 0 3 A

Output resistance is given by

R o u t = Δ V c Δ i c = 0 . 5 0 . 5 × 1 0 3 = 1 0 4 Ω = 1 0 k Ω .

...Read more

i b = 5 0 . 7 8 . 6 = 0 . 5 m A

I c = β I b = 1 0 0 × 0 . 5   m A

By using 

V C E = V C C I C R L = 1 8 5 0 × 1 0 3 × 1 0 0 = 1 3   V

Photodiode operate in reverse bias. The photocurrent increases initially and saturates fi

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