In the given circuit of potentiometer, the potential difference E across AB (10m length) is larger than E₁ and E₂ as well. For key K₁ (closed), the jokey is adjusted to touch the wire at point J₁ so that there is no deflection in the galvanometer. Now the first battery (E₁) is replaced by second battery (E₂) for working by making K₁ open and K₂ closed. The galvanometer gives then null deflection at J₂. The value of   $\frac{E_1}{E_2}is\frac{a}{b},$ where a = …………….

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