In the given circuit of potentiometer, the potential difference E across AB (10m length) is larger than E1 and E2 as well. For key K1 (closed), the jokey is adjusted to touch the wire at point J1 so that there is no deflection in the galvanometer. Now the first battery (E1) is replaced by second battery (E2) for working by making K1 open and K2 closed. The galvanometer gives then null deflection at J2. The value of E 1 E 2 i s a b , where a = …………….

In the given circuit of potentiometer, the potential difference E across AB (10m length) is larger than E₁ and E₂ as well. For key K₁(closed), the jokey is adjusted to touch the wire at point J₁ so that there is no deflection in the galvanometer. Now the first battery (E₁) is replaced by second battery (E₂) for working by making K₁ open and K₂ closed. The galvanometer gives then null deflection at J₂. The value of $\frac{E_{1}}{E_{2}} i s \frac{a}{b},$ where a = …………….

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6 months ago

$\frac{E_{1}}{E_{2}} = \frac{380}{760} = \frac{1}{2}$

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