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In the given figure, the emf of the cell is 2.2V and if internal resistance is 0.6 Ω . Calculate the power dissipated in the whole circuit:

Option 1 -

2.2W

Option 2 -

0.65W

Option 3 -

4.4W

Option 4 -

1.32W

0 4 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 1


    Detailed Solution:

    R e q = 0 . 6 Ω + 4 × 1 2 4 + 1 2 × 6 × 8 6 + 8 4 × 1 2 4 + 1 2 + 6 × 8 6 + 8 Ω

    = 0 . 6 Ω + 3 × 4 8 1 4 3 + 4 8 1 4 Ω

    = 0 . 6 Ω + ( 1 4 4 / 1 4 ) Ω ( 9 0 1 4 )

    = 0 . 6 Ω + 1 . 6 Ω = 2 . 2 Ω

    p = v 2 R e q = ( 2 . 2 V ) 2 2 . 2 Ω = 2 . 2 W

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