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In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm. When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm. The ratio of the emf of two cells, ε₁/ε₂,, is:

 

Option 1 -

4/3

Option 2 -

8/5

Option 3 -

3/2

Option 4 -

5/3

0 3 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:

    ε? = 250 × Potential Gradient
    ε? + ε? = 400 × Potential Gradient
    (ε? )/ (ε? + ε? ) = 250/400 = 5/8
    By solving above
    ε? /ε? = 5/3

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