<p><strong>In the hydrogen spectrum, <math><mrow><mi>λ</mi></mrow></math> be the wavelength of first transition line of Lyman series. The wavelength difference will be <math><mrow><mo>"</mo><mi>a</mi><mi>λ</mi><mo>"</mo></mrow></math> between the wavelength of 3rd transition line of Paschen series and that 2nd transition line B Balmer series where a = __________.</strong></p>

For first line of Lyman1λ=R (1−14)=R34λ=43R3rd line (Paschen)1λ3=R (132−162)=R9×342nd line (B almer)1λ2=R (122−142)=R4×34a (43R)=203R⇒a=5

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Physics Class 12th Nuclei Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen

In the hydrogen spectrum, $λ$ be the wavelength of first transition line of Lyman series. The wavelength difference will be $" a λ "$ between the wavelength of 3rd transition line of Paschen series and that 2nd transition line B Balmer series where a = __________.

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Vishal Baghel | Contributor-Level 10

2 months ago

For first line of Lyman

$\frac{1}{λ} = R (1 - \frac{1}{4}) = R \frac{3}{4}$

$λ = \frac{4}{3 R}$

3rd line (Paschen)

$\frac{1}{λ_{3}} = R (\frac{1}{3^{2}} - \frac{1}{6^{2}}) = \frac{R}{9} \times \frac{3}{4}$

2nd line (B almer)

${\frac{1}{λ}}_{2} = R (\frac{1}{2^{2}} - \frac{1}{4^{2}}) = \frac{R}{4} \times \frac{3}{4}$

$a (\frac{4}{3 R}) = \frac{20}{3 R} \Rightarrow a = 5$

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In the hydrogen spectrum, $λ$ be the wavelength of first transition line of Lyman series. The wavelength difference will be $" a λ "$ between the wavelength of 3rd transition line of Paschen series and that 2nd transition line B Balmer series where a = __________.

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In the hydrogen spectrum, λ be the wavelength of first transition line of Lyman series. The wavelength difference will be "aλ" between the wavelength of 3rd transition line of Paschen series and that 2nd transition line B Balmer series where a = __________.

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In the hydrogen spectrum, $λ$ be the wavelength of first transition line of Lyman series. The wavelength difference will be $" a λ "$ between the wavelength of 3rd transition line of Paschen series and that 2nd transition line B Balmer series where a = __________.