In the reported figure, there is a cyclic process ABCDA on a sample of 1mol of a diatomic gas. The temperature of the gas during the process A→B and C→D are T? and T? (T? > T?) respectively. Choose the correct option out of the following for work done if processes BC and DA are adiabatic.

Option 1 -

W_AB = W_DC

Option 2 -

W_AD = W_BC

Option 3 -

W_BC < W_AD

Option 4 -

W_BC + W_DA > 0

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago
    Correct Option - 3


    Detailed Solution:

    A→B & D→C (isothermal process)
    So, TA = TB & TD = TC. Now B→C & D→A (adiabatic process)
    |WBC| = nR/ (γ-1) (TB - TC)
    |WAD| = nR/ (γ-1) (TA - TD) = nR/ (γ-1) (TB - TC)
    ∴ |WBC| = |WAD|

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