Kindly consider the following

f(x)={2x23x+2x2,x25,x=2

0 3 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    3 months ago

    This is a Short Answer Type Questions as classified in NCERT Exemplar

    Sol:

    f(x)=2x23x2x2=2x24x+x2x2=2x(x2)+1(x2)x2=(2x+1)(x2)x2=2x+1limx2f(x)=2x+1=limh02(2h)+1=4+1=5limx2+f(x)=2x+1=limh02(2+h)+1=4+1=5limx2f(x)=5Aslimx2f(x)=limx2+f(x)=limx2f(x)=5Hence,f(x)iscontinuousatx=2.

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Raj Pandey

Based on theory

V
Vishal Baghel

z² × (13.6) (1 - ¼) = 3 × (13.6)
z = 2 . (i)
h/√2mk? = (1/2.3) × h/√2mk?
=> k? = (2.3)²k? = 5.25k? (ii)
Now, k? = E? - Φ
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  K . E 1 = 1 2 3 0 8 0 0 ? - (i)

  K . E 2 = 2 K . E 1 = 1 2 3 0 5 0 0 ? - (ii)

from (i) & (ii)

? = 0 . 6 1 5  ev

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Vishal Baghel

hu = hu0 + K.E

Cases u = 2u0

h2u0 = hu0 + K.E1

K.E1 = hu0

1 2 m v 1 2 = h υ 0

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Now, cases 2

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A
alok kumar singh

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- p=100W

λ 1= 1nm

λ 2= 500nm

Also n1and n2 represent number of photon of x-rays and visible light emitted from the two sources per sec

E/t=P=n1hc/ λ 1=n2hc/ λ 2

So n1/ λ 1 = n2/ λ 2

So n1/n2= 1/500

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