Radiation from hydrogen gas excited to first excited state is used for illuminating certain metallic plate. When the same plate is exposed to the radiation from some unknown hydrogen like gas excited to the same level it is found that de-Broglie wavelength of fastest photoelectron has decreased by 2.3 times. It is given that energy corresponding to longest wavelength of Lyman series of the unknown gas is 3 times the ionization energy of hydrogen gas (13.6eV). The work function (in eV) of the metallic plate is ______. [Take (2.3)2 = 5.25]

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4 months ago

z² * (13.6) (1 - ¼) = 3 * (13.6)
z = 2 . (i)
h/√2mk? = (1/2.3) * h/√2mk?
=> k? = (2.3)²k? = 5.25k? (ii)
Now, k? = E? - Φ
k? = E? - Φ = z²E? - Φ
∴ k? /k? = (10.2 - Φ)/ (4 * 10.2 - Φ) = 1/5.25
=> Φ = 3eV

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Physics Ncert Solutions Class 12th 2023

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