Match the thermodynamics processes taking place in a system with the correct conditions. In the table: $Δ Q$ is the heat supplied, $Δ W$ is the work done and $Δ U$ is change in internal energy of the system. Match the following:

Option 1 - (A) (I) <math> <mo>→</mo> </math> (B); (II) <math> <mo>→</mo> </math> (D); (III) <math> <mo>→</mo> </math> (A); (IV) <math> <mo>→</mo> </math>  (C)

Option 2 - (B) (I) <math> <mo>→</mo> </math> (A); (II) <math> <mo>→</mo> </math> (A); (III) <math> <mo>→</mo> </math> (B); (IV) <math> <mo>→</mo> </math>  (C)

Option 3 - (C) (I) <math> <mo>→</mo> <mo>(</mo> <mi mathvariant="normal">A</mi> <mo>)</mo> </math> ; (II) <math> <mo>→</mo> </math> (B); (III) <math> <mo>→</mo> </math> (D); (IV) <math> <mo>→</mo> </math> (D)

Option 4 - (D) <math> <mo>(</mo> <mi mathvariant="normal">I</mi> <mo>)</mo> <mo>→</mo> <mo>(</mo> <mi mathvariant="normal">B</mi> <mo>)</mo> </math> ; (II) <math> <mo>→</mo> </math> (A); (III) <math> <mo>→</mo> </math> (D); (IV) <math> <mo>→</mo> </math>  (C)

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Alok Kumar Singh | Contributor-Level 10

7 months ago

Correct Option - 4

Detailed Solution:

Sol. $? v$

$\Rightarrow m v = 16 {m v}_{1}$

$\Rightarrow V_{1} = \frac{V}{16}$

$\Rightarrow Δ k$ loss $= \frac{1}{2} {m v}^{2} - \frac{1}{2} (16 m) {(\frac{V}{16})}^{2}$

$\Rightarrow \frac{1}{2} {m v}^{2} (\frac{15}{16})$

$%$ loss $= \frac{15}{16} * 100 = 93.75 %$

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