n mole of perfect gas undergoes a cyclic process ABCA (see figure) consisting of the following processes.

A->B  : Isothermal expansion at temperature T so that the volume is doubled from V1 to V2 and Pressure changes from P1 to P2.

B->C  : Isobaric compression at pressure P2 to initial volume V1.

C->A  : Isobaric change leading to change of pressure from P2 to P1.

Total work done in the complete cycle ABCA is:

 

Option 1 -

n R T ( I n 2 + 1 2 )

Option 2 -

n R T ( I n 2 1 2 )

Option 3 -

0

Option 4 -

nRTIn2

0 2 Views | Posted 4 weeks ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    4 weeks ago
    Correct Option - 3


    Detailed Solution:

    W A B = n R T l n 2 V 1 V 1 = n R T l n 2 .

    W B C = P 2 ( V 1 2 V 1 ) = P 2 V 1 = 1 2 n R T                         

    [At B, 2P2 V1 = nRT]

    W C A = 0   [CA is isochoric process].

    W A B C A = W A B + W B C + W C A = n R T ( l n ( 2 ) 1 2 )            

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