On the basis of dimensions, decide which of the following relations for the displacement of a particle undergoing simple harmonic motion is not correct:
(a) y = a sin 2πt/ T
(b) y =a sin v t.
(c) y =
sin(
)
(d) y =a
(sin
)
On the basis of dimensions, decide which of the following relations for the displacement of a particle undergoing simple harmonic motion is not correct:
(a) y = a sin 2πt/ T
(b) y =a sin v t.
(c) y = sin( )
(d) y =a (sin )
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1 Answer
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This is a multiple choice answer as classified in NCERT Exemplar
(b, c) for (c) LHS = [L]
RHS= [L/T]=LT-1
LHS RHS
Hence is c option is not correct.
In option (b) dimension of angle is vt i.e =L
RHS= L.L=L2 and LHS = L
LHS RHS
So option b is also not correct
LHS and RHS in both equation B and C are not equal.
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Viscosity = Pascal . Second
=
= x = 1, x + 2y = -1, -x + z = 1
y = -1, Z = 0
Viscosity = [P1A-1T0]
1 msD = 1mm
10 vsD = 9msD
1vsD = 0.9 MsD
L.C. = 1MSD – 1VSD = 1 – 0.9 = 0.1 mm
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Reading = MSR + VSR + correction
= 4.1 cm + 6 * .01 cm + (-0.04 cm) = (4.1 + 0.06 – 0.04) cm
= 4.12 cm = 412 * 10-2 cm
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