Production of iron in blast furnace follows the following equation

$F{e}_3{O}_4\left(s\right)+4CO\left(g\right)\to 3Fe\left(I\right)+4C{O}_2\left(g\right)$

When 4.640 kg of Fe₃O₄ and 2.520 kg of CO are allowed to react then the amount of iron (in g) produced is:

[Given : Molar Atomic mass (g mo^-1); Fe = 56

 Molar Atomic mass (g mol^-1); O = 16

Molar Atomic mass (g mol^-1); C = 12]

<p>Moles of Fe₃O₄ = &lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1814280453"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;&nbsp;<span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>4</mn> <mo>.</mo> <mn>6</mn> <mn>4</mn> <mo>*</mo> <mn>1</mn> <msup> <mrow> <mn>0</mn> </mrow> <mrow> <mn>3</mn> </mrow> </msup> </mrow> <mrow> <mn>2</mn> <mn>3</mn> <mn>2</mn> </mrow> </mfrac> <mo>=</mo> <mn>2</mn> <mn>0</mn> </mrow> </math> </span></p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Moles of CO = &lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1026" DrawAspect="Content" ObjectID="_1814280454"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;&nbsp;<span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>2</mn> <mo>.</mo> <mn>5</mn> <mn>2</mn> <mo>*</mo> <mn>1</mn> <msup> <mrow> <mn>0</mn> </mrow> <mrow> <mn>3</mn> </mrow> </msup> </mrow> <mrow> <mn>2</mn> <mn>8</mn> </mrow> </mfrac> <mo>=</mo> <mn>9</mn> <mn>0</mn> </mrow> </math> </span></p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; So limiting reagent = Fe₃O₄</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; So moles of Fe formed = 60</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Weight of Fe = 60 * 56 = 3360</p>

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