Student A and Student B used two screw gauges of equal pitch and 100 equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is 0.322 cm. The absolute value of the difference between the final circular scale readings observed by the students A and B is _______. [Figure shows position of reference 'O' when jaws of screw gauge are closed]. Given pitch = 0.1 cm.
(Figure A shows a positive zero error with the 5th division of the circular scale coinciding with the reference line. Figure B shows a negative zero error with the 92nd division of the circular scale coinciding with the reference line.)

 

0 2 Views | Posted a month ago
Asked by Shiksha User

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  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    a month ago

    Difference in Reading = Positive Zero Error - Negative Zero Error
    = (+5) - [- (100-92)]
    = 5 - [-8]
    = 13

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