Student A and Student B used two screw gauges of equal pitch and 100 equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is 0.322 cm. The absolute value of the difference between the final circular scale readings observed by the students A and B is _______. [Figure shows position of reference 'O' when jaws of screw gauge are closed]. Given pitch = 0.1 cm.
(Figure A shows a positive zero error with the 5th division of the circular scale coinciding with the reference line. Figure B shows a negative zero error with the 92nd division of the circular scale coinciding with the reference line.)
Student A and Student B used two screw gauges of equal pitch and 100 equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is 0.322 cm. The absolute value of the difference between the final circular scale readings observed by the students A and B is _______. [Figure shows position of reference 'O' when jaws of screw gauge are closed]. Given pitch = 0.1 cm.
(Figure A shows a positive zero error with the 5th division of the circular scale coinciding with the reference line. Figure B shows a negative zero error with the 92nd division of the circular scale coinciding with the reference line.)
Difference in Reading = Positive Zero Error - Negative Zero Error
= (+5) - [- (100-92)]
= 5 - [-8]
= 13
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From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
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Physics NCERT Exemplar Solutions Class 11th Chapter Fifteen 2025
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