Ten charges are placed on the circumference of a circle of radius $10 s$ with constant angular separation between successive charges. Alternate charges 1, 3, 5, 7, 9 have charge (+q) each, while $2,4, 6,8, 10$ have charge (-q)each. The potential v and the electric field E at the centre of the circle are respectively: (Take V = 0 at infinity)

Option 1 -

Option 2 -

Option 3 -

Option 4 -

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1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

a month ago

Correct Option - 3

Detailed Solution:

Potential of centre, = V =
Vc = K (Σq)/R
Vc = K (0)/R = 0
Electric field at centre E_B = E_B = ΣE
Let E be electric field produced by each

charge at the centre, then resultant electric field will be
Ec = 0, since equal electric field vectors are acting at equal angle so their resultant is equal to zero.

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