Ten charges are placed on the circumference of a circle of radius 10 s with constant angular separation between successive charges. Alternate charges 1, 3, 5, 7, 9 have charge (+q) each, while 2,4 , 6,8 , 10  have charge  (-q)each. The potential v and the electric field  E at the centre of the circle are respectively: (Take V = 0  at infinity)

Option 1 - <p>a</p>
Option 2 - <p>ba</p>
Option 3 - <p>c</p>
Option 4 - <p>d</p>
6 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
5 months ago
Correct Option - 3
Detailed Solution:

Potential of centre, = V =
Vc = K (Σq)/R
Vc = K (0)/R = 0
Electric field at centre E_B = E_B = ΣE
Let E be electric field produced by each

charge at the centre, then resultant electric field will be
Ec = 0, since equal electric field vectors are acting at equal angle so their resultant is equal to zero.

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Physics Electrostatic Potential and Capacitance 2025

Physics Electrostatic Potential and Capacitance 2025

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