The activity of a radioactive material is 2.56 × 10-3 Ci. If the half life of the material is 5 days, after how many days the activity will become 2 × 10-5 Ci?
The activity of a radioactive material is 2.56 × 10-3 Ci. If the half life of the material is 5 days, after how many days the activity will become 2 × 10-5 Ci?
Option 1 -
30 days
Option 2 -
35 days
Option 3 -
40 days
Option 4 -
25 days
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1 Answer
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Correct Option - 2
Detailed Solution:A0 = 2.56 * 10-3Ci
A = 2 * 10-15Ci
A =
2n = 128
n = 7
t = 7 * t1/2
= 7 * 5 = 35 days
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Q = [4 *4.0026 – 15.9994] *931.5 MeV
Q = 10.2 MeV
-(1)
for B,
for B,
-(2)
The reaction is X²? → Y¹²? + Z¹²?
Binding energies per nucleon are: X=7.6 MeV, Y=8.5 MeV, Z=8.5 MeV.
Gain in binding energy (Q) = (Binding energy of products) - (Binding energy of reactants)
Q = (120 × 8.5 + 120 × 8.5) - (240 × 7.6) MeV
Q = (2 × 120 × 8.5) - (240 × 7.6) MeV = 2040 - 1824 = 216 MeV.
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