The binding energy (in MeV) of a nitrogen nucleus $\left({}_7^{14}N\right)$  is :

(Given mass of nucleus $m\left({}_7^{14}N\right)=14.00307u$ , mass of proton $m_p=1.00783u$ , mass of neutron $m_n=1.00867u$ and $1u=931.5\mathrm{M}\mathrm{e}\mathrm{V}/{\mathrm{c}}^2$  )

Find the binding energy per neucleon for ${}_{50}^{120}\mathrm{S}\mathrm{n}$ . Mass of proton ${\mathrm{m}}_{\mathrm{p}}=\left(\mathrm{A}\right)1.00783\mathrm{U}$ , mass of neutron ${\mathrm{m}}_{\mathrm{n}}=\left(\mathrm{A}\right)1.00867\mathrm{U}$ and mass of tin nucleus ${\mathrm{m}}_{\mathrm{S}\mathrm{n}}=119.902199\mathrm{U}$ . (take $1\mathrm{U}=931\mathrm{M}\mathrm{e}\mathrm{V}$  )
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