The change in the magnitude of the volume of an ideal gas when a small additional pressure ΔP is applied at a constant temperature, is the same as the change when the temperature is reduced by a small quantity ΔT at constant pressure. The initial temperature and pressure of the gas were 300 K and 2 atm. respectively. If |ΔT| = C|ΔP| then value of C in (K/atm) is ….


2 Views|Posted 5 months ago
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V
5 months ago

T = constant
P = constant

PV = nRT

PdV = nRdT

PdV + VdP = 0

ΔV = nRΔT/P

dV = (-)VdP/P
|ΔV| = V (ΔP/P)
V/P ΔP = nRΔT/P
ΔT = V/nR ΔP
C = V/nR T/P = 300/2 = 150

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Physics Thermodynamics 2025

Physics Thermodynamics 2025

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